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NIMCET Previous Year Questions (PYQs)

NIMCET Probability Distribution PYQ

NIMCET PYQ
The mean and variance of a random variable X having binomial distribution are 4 and 2 respectively. The P(X = 1) is





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NIMCET Previous Year PYQNIMCET NIMCET 2017 PYQ

Solution

np = 4

npq = 2

q = 1/2, p = 1/2, n = 8

p(X = 1) = 8C1 (1/2)(1/2)7

NIMCET PYQ
If  is the mean of distribution of x, then usual notation  is





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NIMCET Previous Year PYQNIMCET NIMCET 2017 PYQ

Solution

Mean Deviation from mean is Zero.

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